0=25x^2+10x-8

Solution for 0=25x^2+10x-8 equation:

0=25x^2+10x-8

We move all terms to the left:

0-(25x^2+10x-8)=0

We add all the numbers together, and all the variables

-(25x^2+10x-8)=0

We get rid of parentheses

-25x^2-10x+8=0

a = -25; b = -10; c = +8;
Δ = b2-4ac
Δ = -102-4·(-25)·8
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-30}{2*-25}=\frac{-20}{-50}
=2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+30}{2*-25}=\frac{40}{-50}
=-4/5
$